PLC Program for Conveyor Motor
Write ladder logic for the simple ON/OFF of conveyor motor and lamp indication.
1. Switch 1 ON —— conveyor motor ON
2. Switch 2 and switch3 ON ——- lamp 1 ON & lamp2 ON
3. Switch 4 or switch5 ON —– conveyor motor OFF
4. Switch 6 ON —– lamp 1 OFF, lamp2 OFF
When you turn ON switch 1 for the first time, conveyor motor should ON.
When Switch 2 ON and switch 3 ON (Both are in ON Condition) should make Lamp 1 & 2 should go ON.
When Switch 4 or Switch 5 (Anyone ON) will make conveyor motor (Which was already turned ON by switch 1) should go OFF.
When Switch 6 ON then it will make lamps 1 & 2 (Which was already turned ON by switch 2 and switch 3) should go OFF.
PLC Program for Conveyor Motor
PLC Program Description:
Rung 0:
When switch 1 is pressed, the motor will turn ON.
Switch 4 and 5 are connected as normally closed contact in series with the output which will make output to go OFF when anyone goes ON.
Rung 1:
Switch 2 and 3 are connected as normally open contact in series with the output which will make output lamp 1 and 2 to go ON only if both are ON.
Switch 6 is connected as normally closed contact to break the power line when it goes ON.
Author: Hema
Training Course: Allen Bradley PLC Course
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I’M HERE FOR CHECH MY CIRCIUT OR PROGRAMMINGLITTLE BIT DIFFERENCE ONLY ,
SW4&SW5 ARE PARELLEL IN CLOSE CONTACT .
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I made same program like you.
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